3.25.32 \(\int \frac {1}{1+4 \sqrt [3]{x^6}} \, dx\)

Optimal. Leaf size=22 \[ \frac {x \tan ^{-1}\left (2 \sqrt [6]{x^6}\right )}{2 \sqrt [6]{x^6}} \]

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Rubi [A]  time = 0.01, antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {254, 203} \begin {gather*} \frac {x \tan ^{-1}\left (2 \sqrt [6]{x^6}\right )}{2 \sqrt [6]{x^6}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 + 4*(x^6)^(1/3))^(-1),x]

[Out]

(x*ArcTan[2*(x^6)^(1/6)])/(2*(x^6)^(1/6))

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 254

Int[((a_) + (b_.)*((c_.)*(x_)^(q_.))^(n_))^(p_.), x_Symbol] :> Dist[x/(c*x^q)^(1/q), Subst[Int[(a + b*x^(n*q))
^p, x], x, (c*x^q)^(1/q)], x] /; FreeQ[{a, b, c, n, p, q}, x] && IntegerQ[n*q] && NeQ[x, (c*x^q)^(1/q)]

Rubi steps

\begin {align*} \int \frac {1}{1+4 \sqrt [3]{x^6}} \, dx &=\frac {x \operatorname {Subst}\left (\int \frac {1}{1+4 x^2} \, dx,x,\sqrt [6]{x^6}\right )}{\sqrt [6]{x^6}}\\ &=\frac {x \tan ^{-1}\left (2 \sqrt [6]{x^6}\right )}{2 \sqrt [6]{x^6}}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 22, normalized size = 1.00 \begin {gather*} \frac {x \tan ^{-1}\left (2 \sqrt [6]{x^6}\right )}{2 \sqrt [6]{x^6}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 + 4*(x^6)^(1/3))^(-1),x]

[Out]

(x*ArcTan[2*(x^6)^(1/6)])/(2*(x^6)^(1/6))

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IntegrateAlgebraic [F]  time = 44.78, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{1+4 \sqrt [3]{x^6}} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(1 + 4*(x^6)^(1/3))^(-1),x]

[Out]

Defer[IntegrateAlgebraic][(1 + 4*(x^6)^(1/3))^(-1), x]

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fricas [A]  time = 0.88, size = 6, normalized size = 0.27 \begin {gather*} \frac {1}{2} \, \arctan \left (2 \, x\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+4*(x^6)^(1/3)),x, algorithm="fricas")

[Out]

1/2*arctan(2*x)

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giac [A]  time = 0.15, size = 6, normalized size = 0.27 \begin {gather*} \frac {1}{2} \, \arctan \left (2 \, x\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+4*(x^6)^(1/3)),x, algorithm="giac")

[Out]

1/2*arctan(2*x)

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maple [A]  time = 0.33, size = 17, normalized size = 0.77 \begin {gather*} \frac {x \arctan \left (2 \left (x^{6}\right )^{\frac {1}{6}}\right )}{2 \left (x^{6}\right )^{\frac {1}{6}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1+4*(x^6)^(1/3)),x)

[Out]

1/2*x*arctan(2*(x^6)^(1/6))/(x^6)^(1/6)

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maxima [A]  time = 1.25, size = 6, normalized size = 0.27 \begin {gather*} \frac {1}{2} \, \arctan \left (2 \, x\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+4*(x^6)^(1/3)),x, algorithm="maxima")

[Out]

1/2*arctan(2*x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.05 \begin {gather*} \int \frac {1}{4\,{\left (x^6\right )}^{1/3}+1} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(4*(x^6)^(1/3) + 1),x)

[Out]

int(1/(4*(x^6)^(1/3) + 1), x)

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sympy [A]  time = 0.13, size = 5, normalized size = 0.23 \begin {gather*} \frac {\operatorname {atan}{\left (2 x \right )}}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+4*(x**6)**(1/3)),x)

[Out]

atan(2*x)/2

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